Warriors and 76ers win in 2026 NBA Play-In Tournament

Stephen Curry (Noah Salzman, Wikimedia Commons)

Two more teams have won in the NBA Play-In Tournament this week. After the Portland Trail Blazers and Charlotte Hornets came away with Tuesday wins, the Golden State Warriors and Philadelphia 76ers were winners on Wednesday.

In Philadelphia’s win over Orlando at Philadelphia’s Xfinity Mobile Arena, the 76ers won the Eastern Conference’s 7-8 game by a score of 109-97. With the win, the 76ers clinch the seventh seed in the Eastern Conference and will face the Boston Celtics in the first round. The Magic are not eliminated with the loss. They will now host the Charlotte Hornets on Friday to determine who the eighth seed will be. The winner will play the Detroit Pistons in the opening round.

Point guard Tyrese Maxey of Dallas, Texas led the 76ers in scoring with 31 points. Meanwhile, two Philadelphia players recorded double-doubles. They were shooting guard VJ Edgecombe of Bimini, Bahamas (19 points and 11 rebounds), and center Andre Drummond of Mount Vernon, New York (14 points and 10 rebounds).

Meanwhile, the Warriors defeated the Los Angeles Clippers 126-121. Golden State came through with the win despite being a 5.5 point underdog and the fact they lost seven of eight games. The Warriors star was point guard Stephen Curry of Akron, Ohio. The best three-point shooter in NBA history made seven three pointers on Wednesday, and scored 35 points overall.

The Warriors dominated the fourth quarter. They outscored the Clippers 43-32 for the five point win.

Next up for the Warriors are the Phoenix Suns. They will play for the eighth seed and an opportunity to play against the Oklahoma City Thunder in the Western Conference quarterfinals.